if √a an irrational number prove that√a+√b is irrational
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Step-by-step explanation:
Let us suppose that √a + √b is a rational number.
So, we can write √a + √b as
√a + √b = p/q .........1 where q ≠ 0
Now, squaring on both side, we get
(√a + √b)2 = (p/q)2
=> a + b + 2*√a * √b = p2 /q2
=> a + b + 2*√(ab) = p2 /q2
=> 2*√(ab) = p2 /q2 - (a + b) ............2
Since, √a + √b are rational, So a and b are also rational.
So, RHS of equation 2 is a rational number.
But it is given that √(ab) is an irrational number.
So, LHS of equation 2 is an irrational number.
which contradict our assumption.
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