if a ana1/a are zeros of polynomial 4x2-2x+k-4 find the value of k
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Answer:
Compare 4x² - 2x + ( k - 4 ) with ax² + bx + c ,
a = 4 ,
b = - 2 ,
c = k - 4 ,
Product of the zeroes = c/a
Alpha × 1/alpha = ( k - 4 ) / 4
1 = ( k - 4 ) / 4
4 = k - 4
4 + 4 = k
8 = k
Therefore ,
k = 8
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