Question

if a and 1/a are the zeroes of a polynomial 2x^2-x+8k then value of k is:​

Answer 1

Answer:

I think if we put the the value of x be (a) then the value of k=0.

And when we put the value of x=1/a then the value will be k=-2+a/8.

Answer 2

Step-by-step explanation:

Product of zeroes =c/a

a×1/a =8k/2

1=8k/2

2=8k

k=1/4

-answer