if a and 1/a are the zeroes of the polynomial 4x^2 -2x+(k-4) find the value of k
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quadratic eqn :
4x^2 -2x + (k -4) have two roots a and 1/a
product of roots = constant/coefficient of x^2
a* 1/a = (k -4)/4
1 = (k -4)/4
4 = k -4
k = 8
4x^2 -2x + (k -4) have two roots a and 1/a
product of roots = constant/coefficient of x^2
a* 1/a = (k -4)/4
1 = (k -4)/4
4 = k -4
k = 8
Answered by
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In Quadratic equation
4x^2 - 2x + (k-4)
Product of zeroes = a × 1/a = (k-4)/4
=> 4 = k - 4
= > k = 8
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4x^2 - 2x + (k-4)
Product of zeroes = a × 1/a = (k-4)/4
=> 4 = k - 4
= > k = 8
HOPE IT WILL HELP YOU. . . . . . . . .
PLZ MARK MY ANSWER AS BRAINLIEST AS SOON AS POSSIBLE! ! ! ! ! ! ! ! ! ! !
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