Question

if a and 1/a are the zeros of polynomial 4x^2-2x+(k-4) the value of k is
(a) 4 (b) 8(c)o (d) non of these​

Answer 1

Compare 4x² - 2x + ( k - 4 ) with

ax² + bx + c ,

a = 4 ,

b = - 2 ,

c = k - 4 ,

Product of the zeroes = c/a

Alpha × 1/alpha = ( k - 4 ) / 4

1 = ( k - 4 ) / 4

4 = k - 4

4 + 4 = k

8 = k

Therefore ,

k = 8

Answer 2

Step-by-step explanation:

a, 1/a are the zeros(roots)

product of zeros= c/a

a*1/a= k-4/4

1=k-4/4

4=k-4

8=k

hope it helps mate!!!