Math, asked by aryanb730, 4 months ago

If a and 1/a are the zeros of the quadratic polynomial 2x*2 -x +8k 5hen k is​

Answers

Answered by snehitha2
14

Answer:

The required value of k is 1/4

Step-by-step explanation:

Given :

a and 1/a are the zeros of the quadratic polynomial 2x² - x + 8k

To find :

the value of k

Solution :

The quadratic polynomial is of the form ax² + bx + c

Comparing the given quadratic polynomial with the general form, we get

  • a = 2
  • b = -1
  • c = 8k

From the relation between zeroes and coefficients,

  • Sum of zeroes = -b/a
  • Product of zeroes = c/a

So,

Product of zeroes = c/a

⇒  (a) × (1/a) = 8k/2

⇒   1 = 8k/2

⇒   8k = 1 × 2

⇒   8k = 2

⇒   k = 2/8

⇒   k = 1/4

Therefore, the value of k is 1/4

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