If a and 1/a are the zeros of the quadratic polynomial 2x*2 -x +8k 5hen k is
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Answer:
The required value of k is 1/4
Step-by-step explanation:
Given :
a and 1/a are the zeros of the quadratic polynomial 2x² - x + 8k
To find :
the value of k
Solution :
The quadratic polynomial is of the form ax² + bx + c
Comparing the given quadratic polynomial with the general form, we get
- a = 2
- b = -1
- c = 8k
From the relation between zeroes and coefficients,
- Sum of zeroes = -b/a
- Product of zeroes = c/a
So,
Product of zeroes = c/a
⇒ (a) × (1/a) = 8k/2
⇒ 1 = 8k/2
⇒ 8k = 1 × 2
⇒ 8k = 2
⇒ k = 2/8
⇒ k = 1/4
Therefore, the value of k is 1/4
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