Question

If 'a' and 2 are roots of equations (2x+1 ) (x-2) find the value of 'a'

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Answer 1

Step-by-step explanation:

Given equation 2x2−2(2a+1)x+a(a+1)=0

Let f(x)=2x2−2(2a+1)x+a(a+1)

The condition for a to lie in between the roots is

a.f(a)<0

⇒2a2−2a(2a+1)+a(a+1)<0(∵A=2>0, so f(a)<0)  

⇒−a2−a<0

⇒a2+a>0

⇒a>0 or a<−1.

Answer 2

Answer:

-1/2.

Step-by-step explanation:

(2x+1) (x-2)

×=-1/2,x=2.

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