Question

If A and (2A – 45°) are acute angles such that sin A = Cos(2A – 45°), then tan A is equal to​

Answer 1

Answer:

tan A=sin A/ cos A

tan A= cos(2A-45°)/cos A

tan A= sin(90-2A+45)/cos A

tanA=sin 45°/cos45°

tan 45°=1

answer=1

Step-by-step explanation:

sin A= cos(2A-45)

sin A= sin(90-2A+45)

A=90-2A+45

3A=135

A=45°