If a and 3 are the zeroes of a quadratic polynomial such that alpha +beta = 24 and alpha-beta= 8. Find the quadratic polynom
having alpha and beta as its zeroes.
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Step-by-step explanation:
~Alpha~ +beta =24
~Alpha~ -beta =8
Subtract both equations
2beta=24-8=16
Beta =16/2=8
Alpha =24-8=16
Therefore the equation is
(X-8)(x-16)=0
Therefore the equation is x²-24x+128
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