Question

If a and 3 are the zeroes of p(x)=x^2+x-2, find the value of 1/a - 1/ b​

Answer 1

Answer:

Step-by-step explanation:

P(x)=x²+x-2

Now p(x)=0

=> x²+x-2=0

=> x²+2x-x-2=0

=> x(x+2)-1(x+2)=0

=> (x+2)(x-1)=0

=> x=1 ,-2

So a=1 and b=-2

So 1/a-1/b=1-(-1/2)=1+1/2=3/2