If a and ẞ are the roots of the equation 2x²-3x - 6 = 0. Find the value of
![\frac{1}{ \alpha } \: + \: \frac{1}{ \beta } \frac{1}{ \alpha } \: + \: \frac{1}{ \beta }](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B+%5Calpha+%7D++%5C%3A+++%2B++%5C%3A++%5Cfrac%7B1%7D%7B+%5Cbeta+%7D+)
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Step-by-step explanation:
α and ß are the roots of 2x² - 3x - 6 = 0. Coefficient of x ( b ) = -3. Constant term ( c ) = -6. We know the relationship between zeroes and coefficient of a quadratic polynomial
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2x²- 3x - 6 = 0
So,
α + β = 3/2
αβ = 6/2 = 3
NOW,
1/a + 1/ẞ
(a + ẞ)/aẞ
3/2 / 3
3/2 × 1/3
1/2
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