if a and ß are the zeroes kf the polynomial 2x^2+3x-7 then find a polynomial whose zeroes are a^2/ß and b^2/a
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Step-by-step explanation:
P(x)=x²-3x+7,
sum of zeros of a quadratic polynomial=a+b,
a+b=-(-3)/1=3---(1).
product of zeros=a.b,
a.b=c/a=7/1=7--(2).
to find-->f(x) having zeroes 1/a and 1/b ,
sum of zeroes of f(x)=1/a+1/b=a+b/ab=3/7,
product of zeros of f(x)=1/a×1/b=1/ab=1/7,
f(x)=x²-( sum of zeros)x+ product of zeros,
=x²-3/7x+1/7,
=7x²-3x+1
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