If a and ß are the zeroes of p(x) = x2 – 5x + 3, then find the value of a + ß - aß
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Answered by
0
Answer:
I think -1
2x - 5x + 3
2 + 0 + -3
= -1
Answered by
1
2
Step-by-step explanation:
a=1 b=-5 c=3
alpha+beta=-b/a
-(-5)/1=5/1=5
alpha×beta=c/a
3/1=3
given:- alpha+beta - alphabeta
5-3=2
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