Question

If a and ß are the zeroes of the
bollowing Polynomial f(c), such
that a- B = 1, than find the value
of a
f (x)=x²_50+k​

Answer 1

We have,

f(x)=x2−p(x+1)−c=0

f(x)=x2−px−(p+c)=0             

Since,

α,β are the zeroes of the above polynomial.

So,

α+β=p 

αβ=−(p+c) 

Since,

(α+1)(β+1)=0

αβ+α+β+1=0

−p−c+p+1=0

−c+1=0

c=1