Question

If a and ß are the zeroes of the quadratic polynomial ax^2
+ bx + c, find the value of 1/alpha and 1/beta​

Answer 1

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-b/c

Step-by-step explanation:

ax^2 + bx + c

now,

sum of zeroes=α+β= - b/a

product of zeroes = αβ

so 1/α + 1/β = (α+β) /αβ

= (-b/a) /(c/a)

= - b/c

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Answer 2

Answer:

-b/c

Step-by-step explanation:

is the answer Please mark me as branist