If a and are the zeros of polynomial f(x)=x²+x-3, find the a polynomial whose zeros are a + 2 & B + 2.
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Answer:
x²+3x-1
Step-by-step explanation:
First to calculate a and b.
Since the zeros of any equation are x minus the roots of the equation, finding the roots of x²+x-3 will give the value of a and b.
=x²+x-3
By comparing, a=1, b=1 and c=-3.
x={-b±√(b²-4ac)}/2a
x=[-(1)±√{(1)²-4(1)(-3)}]/2(1)
Either. Or
x=(-1+√13)/2. x=(-1-√13)/2
Therefore a and b are x-{(-1+√13)/2} and x-{(-1-√13)/2}.
To find the other polynomial multiply a+2 with b+2.
Let the other polynomial be g(x).
g(x)=(a+2)(b+2)
g(x)=[x-{(-1+√13)/2}+2][x-{(-1-√13)/2}+2]
g(x)={x+(3+√13)/2}{x+(3-√13)/2}
g(x)=x{x+(3-√13)/2}+(3+√13)/2{x+(3+√13)/2}
g(x)=x²+3x-1
Please mark brainliest, I spent a lot of time on this problem.
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