Question

if a and ß are the zeros of polynomial x³+6x+2 then ,(1/a+1/ß)=?​

Answer 1

ANSWER :–

GIVEN :–

A POLYNOMIAL x² + 6 x + 2 = 0 have two

roots.

${ \bold{ \underline{TO \: \: FIND} : - }} \\ { \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{1}{ \alpha } + \frac{1}{ \beta } }} \\ \\ \\ { \bold{ \green{ \huge{ \underline {solution} : - }}}} \\ \\ { \bold{ = \frac{1}{ \alpha } + \frac{1}{ \beta } }} \\ \\ { \bold{ = \frac{ \alpha + \beta }{ \alpha \beta } }} \\ \\ { \bold{ \: \: \: . \: \: now \: \: we \: \: have \: \: to \: find \: - }} \\ \\ { \bold{ \: \: \: \: \: (1) \: \: sum \: \: of \: \: roots = \alpha + \beta = - \frac{b}{a} = - 6}} \\ \\ { \bold{ \: \: \: \: \: (2) \: \: product \: \: of \: \: roots = \alpha \beta = \frac{c}{a} = 2 }} \\ \\ { \bold{ = \frac{ \alpha + \beta }{ \alpha \beta } }} \\ \\ { \bold{ = \frac{ - 6}{2} }} \\ \\ { \bold{ = - 3}}$