If a and ß are the zeros of the quadratic polynomial f(x) = x^2 - 1, find a quadratic
polynomial whose zeros are and
2a/b and /a2b/
Answers
Answered by
1
Answer:
Step-by-step explanation:
We have, f(x)=x
2
−1=0
⇒ (x−1)(x+1)=0
⇒ x=1 or −1
⇒ α=−1,β=1
New Roots are
β
2α
and
α
2β
=−2 or −2
⇒ Sum of new roots =−4
⇒ Product of new roots =4
∴f(x)=(x
2
+4x+4)
Answered by
3
Answer:
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