Math, asked by niharikachauhan201, 6 days ago

If a and ß are the zeros of the quadratic polynomial f(x) = x² – 5x + 4, find the value 1/a+1/ß-aß​

Answers

Answered by Anonymous
5

Answer:

Step-by-step explanation:

tep-by-step explanation:

1. The given quadratic equation,

x^2-4x+1

Comparing to the general quadratic equation,

ax^2+bx+c

Where,

a= 1, b= -4, c= 1

Given that α and β are zeroes of the polynomial.

From the properties of the zeroes.

Then,

=4-1

=3

2. in the photo

4. Let the first zero be "a"

and second zero be "-a"

sum of zeroes = -b/a

a + (-a) = (8k²-40k)/4

a - a = 2k²-10k

0 = 2k²-10k

0 = 2k (k -5)

2k = 0 , k - 5 = 0

k = 0,. K = 5

hence, k = 5,0

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