Question

If a and ß are zeroes of x2 - x + 4, then find
(i) a + B
(ii) aß
(iii) 1/a + 1/B - aß

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Answer 1

$\alpha + \beta = - b \div a = 1$

$\alpha \beta = c \div a = 4$

$1 \div \alpha + 1 \div \beta - \alpha \beta = \alpha + \beta \div \alpha \beta - \alpha \beta = 1 \div 4 - 4 = - 15 \div 4$