if a and b are 2 sets such that n(a)=15, n(b)=12 and n(a union b)= 21, then what is n(a intersection b)
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Answer:
(A)=15, n(B)=12 & n(AUB)=21
Step-by-step explanation:
n(AUB)=n(A)+n(B)-n(AnB)
36=15+12-n(AnB)
n(AnB)= 15+12- 21
n(AnB)= 27- 21
= 6
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