Question

if A and B are 60 degree then verify sin(A-B)=sinA×cosB-sinB×cosA​

Answer 1

If a and b is 60 then

that we know,

sin(A-B) =sinA×cosB-sinB×cosA

on putting value

sin(60-60)=sin0= 0......

Answer 2

sin(60-60)=sin60×cos60-sin60×cos60

$\frac{ \sqrt{3} }{2} \times \frac{1}{ \sqrt{2} } - \frac{ \sqrt{3} }{2} \times \frac{1}{ \sqrt{2} }$

$\frac{ \sqrt{3} }{2 \sqrt{2} } - \frac{ \sqrt{3} }{2 \sqrt{2} }$

$= 0$

sin(60-60)

sin(0)

=0

hence 0=0