Question

If A and B are actue angles satisfying Sina=Sin B and 2Cos'A= 3Cos’B then A+B =​

Answer 1

Answer:

i think there is some mistake in the question please check it

Step-by-step explanation:

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i may answer you when you get the question correctly

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Answer 2

Answer:

π /2

Step-by-step explanation:

Given, 3cos  2 A + 2cos  2  B=4

⇒2cos  2 B−1=4−3cos  2  A−1

⇒cos2B=3(1−cos  2  A)=3sin  2  A   ..... (1)

and 2cosBsinB=3sinAcosA

sin2B=3sinAcosA     .... (2)

Now, cos(A+2B)=cosAcos2B−sinAsin2B

=cosA(3sin  2  A)−sinA(3sinAcosA)=0     ....[using eqs. (1) and (2)]

⇒A+2B= π  /2

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