If A and B are acute angle find(A+B) given sinA=1÷√5,sinA=1÷√10=
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ABC is a triangle
⎣
⎢
⎢
⎡
sin2A
sinC
sinB
sinC
sin2B
sinA
sinB
sinA
sin2C
⎦
⎥
⎥
⎤
ABC is a triangle
⇒ It may also be equilateral
⇒A=B=C=60
⇒
⎣
⎢
⎢
⎡
sin120
sin60
sin60
sin60
sin120
sin60
sin60
sin60
sin120
⎦
⎥
⎥
⎤
=
⎣
⎢
⎢
⎢
⎢
⎢
⎢
⎡
2
3
2
3
2
3
2
3
2
3
2
3
2
3
2
3
2
3
⎦
⎥
⎥
⎥
⎥
⎥
⎥
⎤
=0
∴det=0
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