If A and B are acute angles and cosec A=secB, find the value of A+B
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Answered by
4
Answer:
cosec (90-A)=Sec (90-B)
secA=sec(90-b)
sec to sec cancel
now,A+B=90degree
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Answered by
2
Answer:
Hey there
cosec A = sec B
Resiprocaling both the sides,
sin A = cos B
sin A = sin (90 - B)
A = 90 - B
A + B = 90
Hence, A + B = 90
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