If A and B are acute angles and sin(A+B)=1, cos(A-B)= √3/4
Find angles A and B
Find tan A and tan B
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find angle A and B
find tan A and tan B
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Hey...
Here is your answer
Step-by-step explanation:
Given, A and B are acute angles
sin(A+B)=1
sin(A+B)=sin90°
A+B=90° [ By left cancellation]
A=90°-B..........(1)
and
cos(A-B)=√3/4
cos(A-B)=√3/2
cos(A-B)=cos60°
A-B=60°. [By left cancellation]
A=60°+B..........(2)
From (1) and (2) ,we get
90°-B = 60°+B
90°-60°=B+B
30°=2B
B=30°/2
B=15°
put value of B=15°in (1)
A=90°-15°
A=75°
therefore A=75°andB=15°
...........
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