Question

if A and B are acute angles of right angled triangle ABC, right angled at C, prove that sin square A + Sin square B =1​

Answer 1

Step-by-step explanation:

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Answer 2

sin A=(BC/AB)

sin B=(AC/AB)

NOW FROM EQUATION WE HAV

(BC/AB)^2 + (AC/AB)^2

THEREFORE,

(BC^2 + AC^2)/AB^2 SINCE, BY PYTHAGORES THEROREM WE GET

= (AB)^2/(AB)^2

=1

PROVED