Question

If A and B are acute angles such that sinA =cos B, prove that (A+B) =90 degree

Answer 1

Answer:

Sin 45 + Cos 45

Step-by-step explanation:

sin 45 = 1

cos 45= 1

now we get

sin 45 = cos 45

then , sin 45+ cos 45

sin (45 + 45 ) [ sin = cos ]

that means A+ B = 90

Answer 2

$\huge \boxed{ \boxed{ \mathfrak \red{Answer - }}}$

$\sin \: A = \cos \: B \\ \implies \sin \: A = \sin(90 \degree - B ) \\ \implies \: A = 90 \degree - B \\ \implies \: A + B = 90 \degree$

$\boxed{ \underline{ \underline \bold{Proved }}}$