Question

if A and B are acute angles such that sinA=sinB then proove that angle A=angleB ​

Answer 1

Answer. ∴ AC = k × PR and AB = k × PQ From right ΔACB, by Pythagoras theorem we have AB2 = AC2 + BC2 ⇒ (k × PR)2 = (k × PQ) 2 + BC2 ⇒ k2 × PR2 = k2 × PQ2 + BC2 ⇒ BC2 = k2 × PR2 – k2 × PQ2 = k2[PR2 – PQ2]

$bc = k \sqrt{(pr {}^{2} } - pq {}^{2} )$

From right ΔPRQ, by Pythagoras theorem we have PQ2 = PR2 + QR2 ⇒ QR2 = PQ2 – PR2 Hence ΔACB ~ ΔPRQ (SSS similarity criterion) ∴ ∠B = ∠Q

Answer 2

Hey Mate

Your answer.

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