iF A and B are acute angles such that tan A = 1/3, tan B = 1/2and
tan (A+B) = tan Atan B /1-tan A Tan B show that A + B = 45.
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We have tan(a+b) =tana+tanb/1-tana × tanb
tan(a+b) =1/2+1/3÷1-1/2×1/3
5/6÷5/6
5/6×6/5
=1
tan(a+b) =then 45°......since tan 45°=1
=a+b=45°
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