If A and B are acute angles such that tanA=1/2, tanB=1/3 and tan(A+B)=tanA+tan B/1-tanAtanB,find A+B
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tan(A+B)=tanA+tan B/1-tanAtanB
=(1/2+1/3)/1-1/2*1/3
=5/6/5/6=1
A+B=45
=(1/2+1/3)/1-1/2*1/3
=5/6/5/6=1
A+B=45
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