Question

If A and B are acute angles such that tanA=1/3, tanB=1/2 and tan(A+B)= tanA+tanB/1-tanA tanB Pls solve it fast...

Answer 1

Answer:

let try

Step-by-step explanation:

tan(A+B)=tanA+tanB/1-tanAtanB

=1/3+1/2/1-1/3(1/2)

=5/6/1-1/6

=5/6(6/5)=1

hope it helps you