If A and B are angles of a right angled triangle ABC right angled triangle at C prove that sin2 A + sin2 B = 1
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SOLUTION:-
Triangle ABC is right angled at C.
So,
According to the question;
C= 90°
A+B + C= 180° [property of ∆]
A+ B+ 90°= 180°
A+B= 180° -90°
A+B = 90°
B= 90° - A
So,
sin² A + sin²B
=) sin²A + sin² (90- A)
=)sin²A +cos² A
[because sin(90°-A)=cosA]
=) sin²A + cos²A = 1
Proved.
Hope it helps ☺️
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