Math, asked by nehaheleenadan, 1 month ago

if A and B are any two events P(A) = 1/4 P(B)=. 1/3 p(AnB)= 1/6 find p(A or B) and P(nAA and not B)​

Answers

Answered by kingAakash777
2

Answer:

this is the answer

P(A')=1/4 so P(A)=3/4

P(AUB)'=1/6, P(AUB)=5/6

P(A∩B)=1/4

P(AUB)=P(A)+P(B)-P(A∩B)=3/4+P(B)-1/4

5/6=1/2+P(B)

P(B)=2/6=1/3

P(A)*P(B)=1/3*3/4=1/4=P(A∩B)

A and B are independent but not equally likely

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