if A and B are any two events P(A) = 1/4 P(B)=. 1/3 p(AnB)= 1/6 find p(A or B) and P(nAA and not B)
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P(A')=1/4 so P(A)=3/4
P(AUB)'=1/6, P(AUB)=5/6
P(A∩B)=1/4
P(AUB)=P(A)+P(B)-P(A∩B)=3/4+P(B)-1/4
5/6=1/2+P(B)
P(B)=2/6=1/3
P(A)*P(B)=1/3*3/4=1/4=P(A∩B)
A and B are independent but not equally likely
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