Math, asked by abhaidgoel06, 10 months ago

If A and B are any two events such that P(A)=1/2 ,P(B)=11/36 and P(AUB)=23/36 then P(A/B)= ----------- * 6/11 11/6 3/8 1/6

Answers

Answered by veenavg78
1

Answer:

P(A')=1/4 so P(A)=3/4

P(AUB)'=1/6, P(AUB)=5/6

P(A∩B)=1/4

P(AUB)=P(A)+P(B)-P(A∩B)=3/4+P(B)-1/4

5/6=1/2+P(B)

P(B)=2/6=1/3

P(A)*P(B)=1/3*3/4=1/4=P(A∩B)

A and B are independent but not equally likely

Answered by SowmyaSunil
1

Answer:

please make as brainlist

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