If A and B are any two events such that P(A)=1/2 ,P(B)=11/36 and P(AUB)=23/36 then P(A/B)= ----------- * 6/11 11/6 3/8 1/6
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Answer:
P(A')=1/4 so P(A)=3/4
P(AUB)'=1/6, P(AUB)=5/6
P(A∩B)=1/4
P(AUB)=P(A)+P(B)-P(A∩B)=3/4+P(B)-1/4
5/6=1/2+P(B)
P(B)=2/6=1/3
P(A)*P(B)=1/3*3/4=1/4=P(A∩B)
A and B are independent but not equally likely
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please make as brainlist
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