if a and b are any two integers such that a>b, then a^2>b^2 . True or false? Give reason.
Answers
Answered by
2
Answer:
Yes Because It Is Given That,
a>b.
Therefore, Now Squaring Both Sides.
That Is, a²>b².
Hope This Will Help u Mate.
Cms:
But it's false...
Answered by
0
Answer:
Step-by-step explanation:
NOT true if a and b are integers.
Example: - 1 > - 2 , but 1 < 4 , where 1 = (- 1)^2 and 4 = (- 2)^2
However it is true if a and b are natural numbers.
a > b ---> a - b > 0
---> (a - b)(a + b) > 0
---> a^2 - b^2 > 0
---> a^2 > b^2
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