if A and B are coefficients of xᴺ in the expansion of (1+x)²ᴺ and (1+x)²ᴺ⁻¹ then,
A). A=2B
B). A=B
C). 2A=B
D). A/B=(2n)!
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1
Answer:
Correct option is
B
2
We know that coefficient of x
r
in the expansion of (1+x)
m
is
m
C
r
Thus A=
2n
C
n
;B=
2n−1
C
n
We have
B
A
=
2n−1
C
n
2n
C
n
=
n!n!
(2n)!
(2n−1)!
(n!)(n−1)!
=
n
2n
=2
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