If a and b are different matrices satisfying a3 = b3 and a2b = b2a, then det (a2 + b2) is
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Given: a and b are different matrices satisfying a³ = b³ and a²b = b²a
To find: det (a² + b²)
Solution:
- Now we have given :
a³ = b³
- It can be written as: a³ - b³ = 0
a²b = b²a
- It can be written as: a²b - b²a = 0
- Now we know that (a² + b²)(a - b) = a³ - a²b + ab² - b³
- So putting the values in it, we get:
a³ - a²b + ab² - b³ = 0
- That means :
(a² + b²) is a zero divisor.
det(a² + b²) = 0
Answer:
So the determinant is 0.
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