Math, asked by saarsarjyoti121, 9 months ago

If A and B are disjoint sets and n(A)=6, n(B) = 5, then n(AUB) = answer​

Answers

Answered by renuagrawal393
17

Answer:

n(AUB)=n(A)+n(B)-n(AnB)

= 6+5-0

=11

hope it helps you....

Answered by pulakmath007
0

n(A ∪ B) = 11

Given :

A and B are disjoint sets and n(A) = 6, n(B) = 5

To find :

The value of n(A ∩ B)

Solution :

Step 1 of 2 :

Write down the given data

Here it is given that , A and B are disjoint sets and n(A) = 6 , n(B) = 5

Since A and B are disjoint sets

∴ A ∩ B = Φ

⇒ n(A ∩ B) = 0

Step 2 of 2 :

Find the value of n(A ∪ B)

n(A ∪ B) = n(A) + n(B) - n(A ∩ B)

⇒ n(A ∪ B) = 6 + 5 - 0

⇒ n(A ∪ B) = 11

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1. If n(A) = 300, n(A∪B) = 500, n(A∩B) = 50 and n(B′) = 350, find n(B) and n(U).

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A∩(BUC) = (A∩B) U (A∩C)

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