Question

If A and B are events of a random
experiment such that P(AUB) = 4/5 , P
(A’UB') = 7/10 , P(B) = 2/5 then P(A)
equals :​

Answer 1

Step-by-step explanation:

there is a mistake in question please check

Answer 2

Given :   P(AUB)  = 4/5 ,  P (A’UB') = 7/10 , P(B) = 2/5  

To Find :  P(A)

Solution:

P(AUB)  = 4/5

P(A'UB")  =  1  - P (A ∩ B)

=> 7/10 =  1  - P (A ∩ B)

=> P (A ∩ B)  = 3/10

P(AUB) = P(A) + P(B) - P (A ∩ B)

=> 4/5  = P(A) + 2/5  -  3/10

=> P(A) = 4/5 - 2/5 +  3/10

=> P(A) =  2/5 +  3/10

=> P(A) =  4/10 +  3/10

=> P(A) =  7/10

Learn More:

Let A denote the event that a person lives in New York City. Let P(A ...

https://brainly.in/question/18172731

Observe the given Venn diagram and write the following sets. (i) A (ii ...

https://brainly.in/question/4557661