if A and B are finite sets, then prove that n(A U B) = n(A) + n(B) - n(A ∩ B)
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Answer:
given series is in arithmetic progression
with a=-12 and d=3
sum of n terms of an AP=n/2(2a+(n-1)d)
=>54=n/2(2(-12)+(n-1)3)
=>54=n/2(-24+3n-3)
=>108=n(3n-27)
dividing with 3 on boths sides, we get
=>36=n²-9n
=>n²-9n-36=0
=>n²-12n+3n-36=0
=>n(n-12)+3(n-12)=0
=>(n+3)(n-12)=0
n=12
I hope this will help u :
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