if a and b are integers, not both of them are zero there exists integers x and y state that (a, b) = ax+ by
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Given an integer s and a positive integer g, if there are integers
x and y with x+y=s and (x,y) =g,
then as g divides x and y, it divides their sum, and
so g divides s.
Conversely suppose that we are given that s=n.g for some integer n.
Take x=g and y=(n-1)g
Then clearly x+y = g+(n-1)g = n.g=s,
Also g is a common divisor of x and y.
If d is any common divisor of x and y then d divides
the gcd of x and y i.e.(x,y)=(g,(n-1)g)=g.
So g is indeed the gcd of
x and y, i.e. x+y=s and
(x,y)=g, as desired
Step-by-step explanation:
hope it's helpful to you
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