English, asked by ravibhilala234, 7 months ago

If A and B are invertiable matrices of the same order such that I (AB)^-1 I = 8 , If I A I =2 then I B I is ​

Answers

Answered by wipronreddy
0

Explanation:

maybe it's helpful for you

Attachments:
Answered by pulakmath007
42

\displaystyle\huge\red{\underline{\underline{Solution}}}

FORMULA TO BE IMPLEMENTED

1.

 \:  \implies \displaystyle \: |  {A}^{ - 1}  | =   \frac{1}{ | A |  } \:

2.

 | \:  AB\: |  \:  =  | \:A \: |  | B |

GIVEN

A and B are invertible matrices of the same order such that

 |{ (AB)}^{ - 1}|  = 8    \:  \: and \:  \:  \:  |A  \: |  = 2

TO DETERMINE

 | \:  B\: |

CALCULATION

 |{ (AB)}^{ - 1}|  = 8

 \implies \displaystyle \:  \frac{1}{ | AB |  } \:  = 8

 \implies \displaystyle \:  \frac{1}{ | A || B |  } \:  = 8

 \implies \displaystyle \:  \frac{1}{ 2|B |  } \:  = 8

 \implies \displaystyle \:  { | B |  } \:  =  \frac{8}{2}  = 4

Similar questions