Question

If A and B are invertible matrices of the same order then (AB)^-1=B^-1 A^-1. Prove it

Answer 1

Step-by-step explanation:

let A =1 and B=2.

case 1, (AB)^-1

(1×2)^-+

= 2^-1

=1/2

case 2, A^-1×B^-1

1^-1 × 2^-1

=1/1 ×1/2

=1/2

proved