If A and B are irrotational, then A×B is *
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Answered by
2
Answer:
Ok
Explanation:
I have given here:
Curl(A→)=0→ and Curl(B→)=0→
So, to prove solenoidal the divergence must be zero i.e.:
=∇⋅(E→×H→)
Where do I go from here? I came across scalar triple product which may be applied here in some way I suppose if ∇ is a vector quantity.
Ok hope it helps you
Answered by
1
Answer:
By problem ∇ × A = 0 and ∇ × B = 0,
it follows that B .(∇ × A) = 0
A. (∇ × B) = 0 Subtracting,
B .(∇ × A) − A.(∇ × B) = 0
Now ∇ .(A × B) = B .(∇ × A) − A.(∇ × B)
Therefore ∇ .(A × B) = 0,
so that (A × B) is solenoidal
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