Question

IF A and B are mutually exclusive events of a random experiment and P(not A) = 0.45. P(AUB) = 0.65 then find P (B).​

Answer 1

Answer:0.10

Step-by-step explanation:for mutually exclusive events, p(a intersection b)=0

P(A')=0.45

P(A)=0.55

P(AUB)=P(A)+P(B)

0.65=0.55+P(B)

0.10=P(B)

Answer 2

Answer:

Step-by-step explanation:

A and B are mutually exclusive events

so, A intersection B = 0

given, p(not A) = 0.45

p(not A) = 1 - p(A)

=> p(A) = 1 - p(not A)

=> 1 - 0.45 = 0.55

now, p(A union B) = p(A)+P(B)-P(A intersect B)

=> 0.65 = 0.55 + P(B) - 0

=> p(B) = 0.65 - 0.55 = 0.10

Therefore, p(B) = 0.10

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