if a and b are natural number s and a-b is divisible by 3 then a3-b3 is divisible by which number
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a3-b3 can be written as (a-b)^3 -3ab(a-b)
=(a-b)((a-b)^2- 3ab)
so as we know that a-b is divisible by 3 so
(a-b)((a-b)^2 -3ab) is also divisible by 3
so a^3-b^3 is divisible by 3
=(a-b)((a-b)^2- 3ab)
so as we know that a-b is divisible by 3 so
(a-b)((a-b)^2 -3ab) is also divisible by 3
so a^3-b^3 is divisible by 3
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