Question

If a and b are positive integer and a²-b²=9×11 , let's write one of the values of each a and b .​

Answer 1

Solution:

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a²-b²=9×11

Here is your answer!!

Identity:a²-b²=(a+b) (a-b)

let on this identify

let (a+b)=11

(a-b)=9

use substitution formula

equation 1.(a+b)=11

equation 2.(a-b)=9

Add both equation

(a+b)=11

+a-b=9 (+b-b will be cut)

2a=20

$a = \frac{20}{2}$

a=10

using equation 1

a+b=11

10+b=11

b=10-11

b=1

A=10

B=1

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