Question

If a and b are positive integers. Show that√2 always lies between a by b and a²-2b² by b(a+b)

Answer 1

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Answer 2

Answer:

$\sqrt{2b} > a \\ so \: \frac{a}{b} < \sqrt{2} \frac{a}{b} < \sqrt{2 < } \frac{a + 2b}{a + b }$

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