if a and b are positive integers show that root 2 alwYS LIES between a/b and a square - 2bsquare/ b(a+b)
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First, let us assume [math]\dfrac{a+2b}{a+b}>\sqrt{2}[/math]. [math]\dfrac{a+2b}{a+b}> \sqrt{2},[/math] [math]\implies a+2b>\sqrt{2}(a+b),[/math] [math]\implies \sq... ... If a^2 + b^2+c^2 =D where a and b are consecutive positive integers and c=ab, how can you show that √D is always an odd integer? 370 Views · If (BE) ²=MPB, ...
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